y^2+12x-4y+40=0

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Solution for y^2+12x-4y+40=0 equation: 


Simplifying
y2 + 12x + -4y + 40 = 0

Reorder the terms:
40 + 12x + -4y + y2 = 0

Solving
40 + 12x + -4y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + 12x + -4y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + 12x + -4y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + 12x + -4y + y2 = 0 + -40
12x + -4y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
12x + -4y + y2 = -40

Add '4y' to each side of the equation.
12x + -4y + 4y + y2 = -40 + 4y

Combine like terms: -4y + 4y = 0
12x + 0 + y2 = -40 + 4y
12x + y2 = -40 + 4y

Add '-1y2' to each side of the equation.
12x + y2 + -1y2 = -40 + 4y + -1y2

Combine like terms: y2 + -1y2 = 0
12x + 0 = -40 + 4y + -1y2
12x = -40 + 4y + -1y2

Divide each side by '12'.
x = -3.333333333 + 0.3333333333y + -0.08333333333y2

Simplifying
x = -3.333333333 + 0.3333333333y + -0.08333333333y2

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